Digital Electronics MCQs
Practice and Learn through MCQs and Quizzes. W3Definitions.com have 427 Digital Electronics MCQs
-8 is equal to signed binary number
- A. 10001000
- B. 00001000
- C. 10000000
- D. 11000000
- Correct Answer: Option A
+12 V supply is given to plates a, d, g, and 0 V to other plates and grid of a VF display. The plates which will glow are
- A. a, d, g
- B. b, c, e, f
- C. all
- D. none
- Correct Answer: Option C
0.10112 = __________ .
- A. 0.687510
- B. 0.680010
- C. 0.010010
- D. 0.500010
- Correct Answer: Option A
1’s complement of 11100110 is
- A. 00011001
- B. 10000001
- C. 00011010
- D. 00000000
- Correct Answer: Option A
10’s complement of 1610 is
- A. 8310
- B. 8410
- C. 3810
- D. 4810
- Correct Answer: Option B
100101.10112 = __________ .
- A. 115.228
- B. 115.548
- C. 215.548
- D. 100.018
- Correct Answer: Option B
1001012 is equal to decimal number
- A. 47
- B. 37
- C. 21
- D. 17
- Correct Answer: Option B
10112 x 1012 = __________ 10
- A. 55
- B. 45
- C. 35
- D. 25
- Correct Answer: Option A
11011 in gray code = __________ .
- A. 100102
- B. 111112
- C. 111002
- D. 100012
- Correct Answer: Option A
11012 – 10012 =
- A. 1000
- B. 0100
- C. 0010
- D. 0001
- Correct Answer: Option B
111012 x 100012 =
- A. 111101101
- B. 111101100
- C. 11110
- D. 1100110
- Correct Answer: Option A
1111 + 11111 =
- A. 101111
- B. 101110
- C. 111111
- D. 011111
- Correct Answer: Option B
127416 – 3A716 = __________ .
- A. ACA16
- B. ACB16
- C. ECD16
- D. AAA16
- Correct Answer: Option C
2’s complement number 00011111 = __________ 10
- A. +31
- B. -31
- C. +11
- D. -11
- Correct Answer: Option A
2’s complement of (-24) =
- A. 11101000
- B. 01001000
- C. 01111111
- D. 00111111
- Correct Answer: Option A
2’s complement of a given 3 or more bit number of non-zero magnitude is the same as the original number if all bits except
- A. MSB are zero
- B. LSB are zero
- C. MSB are 1
- D. LSB are 1
- Correct Answer: Option A
2’s complement of binary number 0101 is
- A. 1011
- B. 1111
- C. 1101
- D. 1110
- Correct Answer: Option A
2’s complement representation of a 16 bit number (one sign bit and 15 magnitude bit) is FFFF. Its magnitude in decimal representation is
- A. 0
- B. 1
- C. 32676
- D. 65, 535
- Correct Answer: Option B
23.610 = __________ 2
- A. 11111.1001
- B. 10111.1001
- C. 00111.101
- D. 10111.1
- Correct Answer: Option B
26810 = __________ .
- A. 10A16
- B. 10B16
- C. 10C16
- D. 10D16
- Correct Answer: Option C
39.1210 = __________ 10
- A. 10111.0001111
- B. 100011.0001111
- C. 100001.0001111
- D. 001111.0001111
- Correct Answer: Option A
4 bit 2’s complement representation of a decimal number is 1000. The number is
- A. + 8
- B. 0
- C. - 7
- D. - 8
- Correct Answer: Option D
718 = __________ .
- A. 1110002
- B. 1110012
- C. 1000012
- D. 1100012
- Correct Answer: Option B
74HCT00 series is
- A. NAND IC
- B. interface between TTL and CMOS
- C. inverting IC
- D. NOR IC
- Correct Answer: Option B
7BF16 = __________ 2
- A. 0111 1011 1110
- B. 0111 1011 1111
- C. 0111 1011 0111
- D. 0111 1011 0011
- Correct Answer: Option B
9’s complement of 1210 is
- A. 2110
- B. 8710
- C. 7810
- D. 7610
- Correct Answer: Option B
9’s complement of 5610 is
- A. 4310
- B. 8410
- C. 6510
- D. 5310
- Correct Answer: Option A
A . 0 =
- A. 1
- B. A
- D. A or 1
- Correct Answer: Option C
A + (B . C) =
- A. A . B + C
- B. A . B + A . C
- C. A
- D. (A + B) . (A + C)
- Correct Answer: Option D
A + A . B =
- A. B
- B. A . B
- C. A
- D. A or B
- Correct Answer: Option C
A 10 MHz square wave clocks 5 bit ripple counter. The frequency of the 3rd FF output is
- A. 2 MHz
- B. 1.25 MHz
- C. 50 MHz
- D. 615 kHz
- Correct Answer: Option B
A 12 bit ADC is operating with 1 μs clock period. Total conversion time is 14 μs. ADC is
- A. flash type
- B. counting type
- C. integrating type
- D. successive approximation type
- Correct Answer: Option C
A 14 pin AND gate IC has __________ AND gates.
- A. 8
- B. 6
- C. 4
- D. 2
- Correct Answer: Option C
A 14 pin NOT gate 1C has __________ NOT gates.
- A. 8
- B. 6
- C. 5
- D. 4
- Correct Answer: Option B
A 16 bit binary adder has
- A. 16 half adders
- B. 16 full adders
- C. one half adders and 15 full adders
- D. 8 half adders and eight full adders
- Correct Answer: Option C
A 16 bit binary adder has
- A. 16 half adders
- B. 16 full adders
- C. one half adders and 15 full adders
- D. 8 half adders and eight full adders
- Correct Answer: Option C
A 3 bit binary adder can add
- A. 2 bits
- B. 2 bits
- C. 3 bits
- D. 8 bits
- Correct Answer: Option C
A 3 bit binary adder should use
- A. 3 full adders
- B. 2 full adders and 1 half adder
- C. 1 full adder and 2 half adders
- D. 3 half adders
- Correct Answer: Option B
A 3 bit up-down counter can count from
- A. 000 to 111
- B. 111 to 000
- C. 000 to 111 and also from 111 to 000
- D. none of the above
- Correct Answer: Option C
A 3 input NAND gate is to be used as inverter. Which of the following will give better results?
- A. The two unused inputs are left open
- B. The two unused inputs are connected to 0
- C. The two unused inputs are connected to 1
- D. None of the above
- Correct Answer: Option C